Chemistry help - Reduction potential!?

in a galvanic cell positivity or negativity of voltmeter depends on how its is connected .
if - near - and + near + it shows positive number and if - near + and + near - it shows negative number.
you can figure it out that Pb is anode because in the correct connection of voltmeter (first one that shows positive numbers) electrons are flowing from Pb to Cu.(electrons always go from anode to cathode)
or you can simply look at electrochemical series .Pb is upper(or more negative) in the electrochemical series and it wants to lose electron so it is anode(-) , where oxidation happens.
so the half equation would be :
Pb----->Pb^2+ + 2e^-

copper electrode is cathode where reduction happens and it's half equation would be:
Cu^2+ + 2e^- ------>Cu