Math question please help! Im failing and this is due at midnight! 10pts for helping!?

The signal from B is inverted by the NOT gate at the bottom left.
I will use b (lower base B) to indicate "NOT-B"

The top gate is an "AND" gate, which, in Boolean notation, is indicated as a multiplication (usually, no symbol. It receives the A signal and the b (inverse of B) and it will fire off a 1 only if both are 1.
Ab = 1 if A=1 AND B=0 (which is the same as b=1)
otherwise, it returns a 0.

The last gate (bottom right) is an OR gate (represented by the addition sign +), it will return a 1 is it gets a 1 from any of the inputs. It only shows a 0 if both are zero.

Its two inputs are b (= NOT-B) and Ab from the top gate.

The output of the OR gate is the only output of the circuit, so the system can be represented by the Boolean equation

Ab + b

If you want to represent all three gates in the equation, then use
A(NOT-B) + (NOT-B)

where NOT- can be replaced by a "tilde"

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If you want to simplify the equation:
NOT_B can be factored out:

(NOT-B)(A + 1) = (NOT-B)(1) = NOT-B

which means that the equivalent circuit could be built with one gate and one input: B with a NOT gate (the inverter)

The system will give a 1 only when B=0, otherwise, it will give 0